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Mohamed120
@Mohamed120
January 2021
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x>0 et y>0
démonter que √x+√y <√(2*(x+y))
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rachidSM2000
(√x-
√y)^2>0
x+y-2
√(xy)>0
x+y>2
√(xy)
2x+2y>2
√(xy)+x+y
2(x+y)>(
√x+
√y)^2
√(2(x+y))>√x+
√y
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x+y-2√(xy)>0
x+y>2√(xy)
2x+2y>2√(xy)+x+y
2(x+y)>(√x+√y)^2
√(2(x+y))>√x+√y