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[tex] > resolucao \\ \\ > progressao \: aritmetica \\ \\ \\ 1 \: ) \: quinquagessimo \: termo \: da \: pa \: (10.7.4..) \\ \\ r = a2 - a1 \\ r = 7 - 10 \\ r = - 3 \\ \\ an = a1 + (n - 1)r \\ an = 10 + (50 - 1) - 3 \\ an = 10 + 49 \times ( - 3) \\ an = 10 + ( - 147) \\ an = 10 - 147 \\ an = - 137 \\ \\ = = = = = = = = = = = = = = = = = = = \\ \\ \\ 2 \: )o \: primeiro \: termo \: da \: pa \\ \\ an = 50 \\ n = 25 \\ r = 2 \\ \\ an = a1 + (n - 1)r \\ 50 = a1 + (25 - 1)2 \\ 50 = a1 + 24 \times 2 \\ 50 = a1 + 48 \\ a1 = 50 - 48 \\ a1 = 2 \\ \\ = = = = = = = = = = = = = = = = = = \\ \\ \\ 3 \: ) \: quantos \: multiplos \: de \: 7 \: entre \: 5 \: e \: 225 \\ \\ \\ a1 = 7 \\ r = 7 \\ an = 224 \\ \\ an = a1 + (n - 1)r \\ 224 = 7 + (n - 1)7 \\ 224 = 7 + 7n - 7 \\ 224 = 7n \\ n = \frac{224}{7} \\ n = 32 \\ \\ \\ > < > < > < > < > < > < > < > > [/tex]

Resposta:

>resolucao>progressaoaritmetica1)quinquagessimotermodapa(10.7.4..)r=a2−a1r=7−10r=−3an=a1+(n−1)ran=10+(50−1)−3an=10+49×(−3)an=10+(−147)an=10−147an=−137===================2)oprimeirotermodapaan=50n=25r=2an=a1+(n−1)r50=a1+(25−1)250=a1+24×250=a1+48a1=50−48a1=2==================3)quantosmultiplosde7entre5e225a1=7r=7an=224an=a1+(n−1)r224=7+(n−1)7224=7+7n−7224=7nn=7224n=32><><><><><><><>>