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Ss07ss03
@Ss07ss03
May 2019
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Bonjour pouvez-vous m'aider sur se devoirs svp:
dans un triangle JKL,rectangle en K,on a:
sin J=12/13
} et JK=5cm
sin L=5/13
donner la valeur exacte de cos J , de cos L de tan J et tan L
merci (:☆
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croisierfamily
Cos(J) = sin(L) = 5/13
tan(J) = 12/5 = 2,4
cos(L) = sin(J) = 12/13
tan(L) = 5/12
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croisierfamily
pourquoi cos(J) = sin(L) ? parce que J + L = 90° ( on dit que les angles sont complémentaires ! )
croisierfamily
tangente(â) = opposé / adjacent . Si tu fais le croquis du triangle rectangle d' hypoténuse JL = 13 cm, tu devrais tout comprendre !
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tan(J) = 12/5 = 2,4
cos(L) = sin(J) = 12/13
tan(L) = 5/12