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brunachauffaill
@brunachauffaill
October 2020
2
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Simplificando a expressão
2i/(1–i) ,
temos:
a. 1+i
b.-1+i
c.i
d.1-i
e.-1-i
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MATHSPHIS
Verified answer
4 votes
Thanks 12
3478elc
Verified answer
2i
=
2i( 1 + i )
=
2i + 2i
²
=
2i - 2
=
2( i - 1)
= i - 1
(1–i) (1-i)(1+i) 1 - i
² 1 + 1 2
3 votes
Thanks 6
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Verified answer
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2i = 2i( 1 + i ) = 2i + 2i² = 2i - 2 = 2( i - 1) = i - 1
(1–i) (1-i)(1+i) 1 - i² 1 + 1 2