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thaissantanabarr
@thaissantanabarr
March 2022
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Preciso urgente... a){8x+y=7 4x+y/3=3
b){5x-y=0 x/2+y/5=3
c)x+y/2=4 2x+3y=-16
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Anúncio Anúncio thaissantanabarr está aguardando sua ajuda. Inclua sua resposta e ganhe pontos.
emicosonia
emicosonia
Preciso urgente...
a){8x+y=7 4x+y/3=3
{ 8x + y = 7
{ 4x + y/3 = 3
8x + y = 7 ---------------isolar o (y)
y = 7 - 8x -------------------------------------substituir (y)
4x + y/3 = 3
y
4x + ------ = 3
3
7 - 8x
4x + -------------- = 3
3
3(4x) + (7 - 8x) = 3(3) fração com igualdade desprezamos o denominador
----------------------------
3
3(4x) + 7 - 8x = 3(3)
12x + 7 - 8x = 9
12x - 8x = 9 - 7
4x = 2
x = 2/4 -----------------divide AMBOS por 2 (simplificando)
x = 1/2
ACHAR O valor de (y)
y = 7 - 8x
y = 7 - 8(1/2)
y = 7 - 8/2
y = 7- 4
y = 3
V = { 1/2; 3}
b){5x-y=0 x/2+y/5=3
{ 5x - y = 0
{ x/2 + y/5 = 3
5x - y = 0----------------isolar o (y)
- y = - 5x
y = (-)(-) 5x
y = + 5x -----------------------substituir o (y)
x/2 + y/5 = 3
x 5x
--- + ------- = 3
2 5
5(x) + 2(5x) = 10(3) idem acima
------------------------
10
5(x) + 2(5x) = 10(3)
5x + 10x = 30
15x = 30
x = 30/15
x = 2 ----------------ACHAR o valor de (y)
y = 5x
y = 5(2)
y = 10
V = { 2; 10}
c)x+y/2=4 2x+3y=-16
{x + y/2 = 4
{2x + 3y = - 16
x + y/2 = 4 ---------------------isolar o (x)
x = 4 - y/2----------------------------------------substituir o (x)
2x + 3y = - 16
2(4-y/2) + 3y = - 16
8 -
2y/2
+ 3y = - 16 ----(ATENÇÃO)
2y/2 = y
8 - y + 3y = - 16
- y + 3y = - 16 - 8
2y = -24
y = - 24/2
y = - 12
achar o valor de (x)
x = 4 - y/2
x = 4 -(-12/2)
x = 4 - (-6)
x = 4 + 6
x = 10
V = { 10; - 12}
brigada!
Anúncio Anúncio
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