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leodrevet
@leodrevet
June 2021
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Factoriser: (les x ne sont pas des fois !!!) les slash sont la barre de fraction aussi))
81+16y²-72y
b²-10b+25
x²+36-12x
(2-x)²+(2-x)(9+x)
4/9p²+4/3pq+q²
(5x+1)²-81
(t+3)²-16
(7d+2)²-(3d+4)²
(2x+1)²-25
(3i+7)²-(i+5)²
2i(i+1)+2i(2+i)
merci d'avance
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ensimev
b²-10b+25=(b-5)²
x²+36-12x=(x-6)²
(2-x)²+(2-x)(9+x)=(2-x)(2-x+9+x)=11(2-x)
4/9p²+4/3pq+q²=(2/3p+q)²
(5x+1)²-81=(5x+1+9)(5x+1-9)=(5x+10)(5x-8)=5(x+2)(5x-8)
(t+3)²-16=(t+3-4)(t+3+4)=(t-1)(t+7)
(7d+2)²-(3d+4)²=(7d+2-3d-4)(7d+2+3d+4)=(4d-2)(10d+6)=2(2d-1)2(5d+3)
=4(2d-1)(5d+3)
(2x+1)²-25=(2x+1-5)(2x+1+5)=(2x-4)(2x+6)=2(x-2)2(x+3)=4(x-2)(x+3)
(3i+7)²-(i+5)²=(3i+7-i-5)(3i+7+i+5)=(2i+2)(4i+12)=2(i+1)4(i+3)=8(i+1)(i+3)
2i(i+1)+2i(2+i)=2i(i+1+2+i)=2i(2i+3)
81+16y²-72y=(9-4y)²
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massirek93
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b²-10b+25=(b-5)²
x²+36-12x=(x-6)²
(2-x)²+(2-x)(9+x)=(2-x)(2-x+9+x)=11(2-x)
4/9p²+4/3pq+q²=(2/3p+q)²
(5x+1)²-81=(5x+1+9)(5x+1-9)=(5x+10)(5x-8)=5(x+2)(5x-8)
(t+3)²-16=(t+3-4)(t+3+4)=(t-1)(t+7)
(7d+2)²-(3d+4)²=(7d+2-3d-4)(7d+2+3d+4)=(4d-2)(10d+6)=2(2d-1)2(5d+3)
=4(2d-1)(5d+3)
(2x+1)²-25=(2x+1-5)(2x+1+5)=(2x-4)(2x+6)=2(x-2)2(x+3)=4(x-2)(x+3)
(3i+7)²-(i+5)²=(3i+7-i-5)(3i+7+i+5)=(2i+2)(4i+12)=2(i+1)4(i+3)=8(i+1)(i+3)
2i(i+1)+2i(2+i)=2i(i+1+2+i)=2i(2i+3)
81+16y²-72y=(9-4y)²