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leodrevet
@leodrevet
June 2021
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factoriser : les x sont des x pas des fois )
(x+4)²-49
(x-4)²-(2x-1)²
121-(x-7)²
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slyz007
Verified answer
(x+4)²-49=(x+4)²-7²=(x+4+7)(x+4-7)=(x+11)(x-3)
(x-4)²-(2x-1)²=(x-4+2x-1)(x-4-2x+1)=(3x-5)(-x-3)
121-(x-7)²=11²-(x-7)²=(11+x-7)(11-x+7)=(x+4)(18-x)
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Verified answer
(x+4)²-49=(x+4)²-7²=(x+4+7)(x+4-7)=(x+11)(x-3)(x-4)²-(2x-1)²=(x-4+2x-1)(x-4-2x+1)=(3x-5)(-x-3)
121-(x-7)²=11²-(x-7)²=(11+x-7)(11-x+7)=(x+4)(18-x)