Bonsoir Pouvez-vous me résoudre ces équation en détaillant bien c'est très important ! Merci :)
1) (4x-2)(7x+1)(12x-6)=0
2) (2x-1)²=(2x-1)(x+3)
3) (2x-1)(x+1)= 5x+5
4) (x²-2x)/(2+x) = 0
5) (x²-9)/(3x)=0
6) ((x/2)-1)/(3-2x)=2
7) (x+1)/(2)+(x+2)/(3)+(x+3)/(4)=12x-1
8)(x+1)²-(2x+2)=0
9)(4x²-9)-2(2x-3)+x(2x-3)=0
Merci de bien détailler !
1) (4x-2)(7x+1)(12x-6)=0
2) (2x-1)²=(2x-1)(x+3)
3) (2x-1)(x+1)= 5x+5
4) (x²-2x)/(2+x) = 0
5) (x²-9)/(3x)=0
6) ((x/2)-1)/(3-2x)=2
7) (x+1)/(2)+(x+2)/(3)+(x+3)/(4)=12x-1
8)(x+1)²-(2x+2)=0
9)(4x²-9)-2(2x-3)+x(2x-3)=0
Merci de bien détailler !
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Bonjour
1) (4x-2)(7x+1)(12x-6)=0
4x -2 = 0
4x = 2
X = 2/4 = 1/2
7x + 1 = 0
7x = -1
X = -1/7
12x -6 = 0
12x = 6
X = 6/12 = 1/2
2) (2x-1)²=(2x-1)(x+3)
(2x-1)^2 -(2x-1)(x+3) = 0
(2x-1)(2x-1-x-3) = 0
(2x-1)(x-4) = 0
2x -1 = 0
2x = 1
X = 1/2
X-4 = 0
X = 4
3) (2x-1)(x+1)= 5x+5
(2x-1)(x+1) -5x -5 = 0
(3x-1)(x+1) -5(x+1) = 0
(X+1)(3x-1-5) = 0
(X+1)(3x-6) = 0
X + 1 = 0
X = -1
3x-6 = 0
3x = 6
X = 6/3 = 2
8)(x+1)²-(2x+2)=0
(X+1)^2 -2(x+1) = 0
(X+1)(x+1-2) = 0
(X+1)(x-1) = 0
X + 1 = 0
X = -1
X-1 = 0
X = 1
9)(4x²-9)-2(2x-3)+x(2x-3)=0
(2x-3)(2x+3) -2(2x-3) + x(2x-3) = 0
(2x-3)(2x+3-2+x) = 0
(2x-3)(3x+1) = 0
2x-3 = 0
2x = 3
X = 3/2
3x +1 = 0
3x = -1
X = -1/3