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Forever410
@Forever410
April 2019
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Quelqu'un pourrait m'aider a résoudre ses équation svp
(x+3)²=0 (x-7)²=0
(9x+6)²=0 (2x+3)(x-2) =0
x²-7x+10=0 x²+8x+16=0
x²-10x+16=0 9x²-12x+4=0
-x²+4x-3=0 -x²+5x-6=0
1/4x² -3x+9=0
x²+6x-7=0
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18janvier
(x+3)² x=-3
(x-7)² x=+7
(9x+6)² x=-6/9
(2x+3)(x-2) x =-3/2 et +2
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(x-7)² x=+7
(9x+6)² x=-6/9
(2x+3)(x-2) x =-3/2 et +2