Réponse :
[tex]tan(a) =\frac{sin(a)}{cos(a)}[/tex]
a. Pour [tex]sin(a) = \frac{1}{3} \:\:et\:\cos(a) = \frac{2\sqrt{2}}{3} }[/tex]
[tex]tan(a)= \frac{\frac{1}{3} }{\frac{2\sqrt{2} }{3} } =\frac{1}{2\sqrt{2}}= \frac{\sqrt{2} }{4}[/tex]
b. Pour [tex]sin(c) = \frac{3}{5} \:\:et\:\cos(c) = \frac{4}{5} }[/tex]
[tex]tan(c)= \frac{\frac{3}{5} }{\frac{4}{5} } = \frac{3}{4}[/tex]
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Réponse :
[tex]tan(a) =\frac{sin(a)}{cos(a)}[/tex]
a. Pour [tex]sin(a) = \frac{1}{3} \:\:et\:\cos(a) = \frac{2\sqrt{2}}{3} }[/tex]
[tex]tan(a)= \frac{\frac{1}{3} }{\frac{2\sqrt{2} }{3} } =\frac{1}{2\sqrt{2}}= \frac{\sqrt{2} }{4}[/tex]
b. Pour [tex]sin(c) = \frac{3}{5} \:\:et\:\cos(c) = \frac{4}{5} }[/tex]
[tex]tan(c)= \frac{\frac{3}{5} }{\frac{4}{5} } = \frac{3}{4}[/tex]