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Jessicaddie
@Jessicaddie
April 2019
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Pouvez vous m'aider svp ?
comment determiner algebriquement l'image de -2 et de 3/7 par f
f(x)=x au carre - x - 6
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64angelmax
F(-2)=-2°2 -2 -6
=4 -2 -6
=-4
f(3/7)=(3/7)°2 -(3/7) -6
=9/49 -(3/7) -6
=-(306/49)
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=4 -2 -6
=-4
f(3/7)=(3/7)°2 -(3/7) -6
=9/49 -(3/7) -6
=-(306/49)