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Jessicaddie
@Jessicaddie
April 2019
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Aider moi svp !!!
je n'arrive pas a faire l'exercice :
soit A(x)= (x-2)(3x+3)-(2x-5) et B(x)=16x²-9
1- factoriser A(x)
2-resoudre A(x)=0
3-factoriser B(x)
merci !!
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SmartAss
J'arrive à resoudre 2 et 3
2- (x-2)(3x+3) - (2x-5) = 0
(x-2)(3x+3) = (2x-5)
x(3x+3) -2(3x+3) = 2x-5
3x² +3x -6x -6 = 2x-5
3x² -3x -6 = 2x-5
3x² = 2x +3x-5+6
3x² =5x +1
x² =5x+1/3
Donc x=√5x+1/3 ou x=√5x+1/3
et 3- B= 16x² -9
=4²x² -3²
=(4x)² -3²
=(4x -3)(4x +3)
J’espèreque c'est juste, et pardon sinon :c
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Pouvez vous m'aider svp ? comment determiner algebriquement l'image de -2 et de 3/7 par f f(x)=x au carre - x - 6
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2- (x-2)(3x+3) - (2x-5) = 0
(x-2)(3x+3) = (2x-5)
x(3x+3) -2(3x+3) = 2x-5
3x² +3x -6x -6 = 2x-5
3x² -3x -6 = 2x-5
3x² = 2x +3x-5+6
3x² =5x +1
x² =5x+1/3
Donc x=√5x+1/3 ou x=√5x+1/3
et 3- B= 16x² -9
=4²x² -3²
=(4x)² -3²
=(4x -3)(4x +3)
J’espèreque c'est juste, et pardon sinon :c