Resposta:
[tex]1.32*10^{-2}m[/tex]
Explicação:
[tex]Dados\\L_0=30m\\T_i=10\ºC\\T_f=50\ºC\\\alpha=22*10^{-6}\ºC^{-1}\\\\Resolucao\\\Delta L=L_0*\alpha*\Delta T\\\Delta L=30*22*10^{-6}*(50-30)\\\Delta L=30*22*10^{-6}*20\\\Delta L=13200*10^{-6}\\\Delta L=1,32*10^{-2}m\\ou \\\Delta L=1,32cm[/tex]
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Resposta:
[tex]1.32*10^{-2}m[/tex]
Explicação:
[tex]Dados\\L_0=30m\\T_i=10\ºC\\T_f=50\ºC\\\alpha=22*10^{-6}\ºC^{-1}\\\\Resolucao\\\Delta L=L_0*\alpha*\Delta T\\\Delta L=30*22*10^{-6}*(50-30)\\\Delta L=30*22*10^{-6}*20\\\Delta L=13200*10^{-6}\\\Delta L=1,32*10^{-2}m\\ou \\\Delta L=1,32cm[/tex]