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Kellypokofans
@Kellypokofans
April 2019
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A) Factorise 4x²-9
b) déduis-en une factorisation de l'expression :
J = 4x²-9+(2x+3)(x-1)
c) résous l'équation J = 0
Merci a ceux qui répondront ! :)
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Verified answer
Bonjour
a)
4x² - 9 = ( 2x-3)(2x+3)
b)
J = 4x² - 9 + (2x + 3)(x-1)
J = (2x-3)(2x+3) + (2x+3)(x - 1)
J = (2x + 3)( 2x - 3 + x - 1)
J = (2x + 3)( 3x - 4)
c)
J = 0 produit de facteurs nul si un facteur est nul soit
2x+3 = 0 pour x = -3/2
ou 3x - 4 = 0 pour x = 4/3
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Bonjoura)
4x² - 9 = ( 2x-3)(2x+3)
b)
J = 4x² - 9 + (2x + 3)(x-1)
J = (2x-3)(2x+3) + (2x+3)(x - 1)
J = (2x + 3)( 2x - 3 + x - 1)
J = (2x + 3)( 3x - 4)
c)
J = 0 produit de facteurs nul si un facteur est nul soit
2x+3 = 0 pour x = -3/2
ou 3x - 4 = 0 pour x = 4/3