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Kellypokofans
@Kellypokofans
April 2019
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Factorisation besoin d'aide SVP !!
Soit F = (3x-5)² - (3x-5) (x+4)
a) développer et réduire F.
b) Factoriser F.
c) Calculer F pour x =1 puis pour x = 4.5
Merci a ceux qui répondront ! :)
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loulakar
Verified answer
Bonjour,
a) (3x-5)^2 - (3x-5) (x+4)
= 9x² -30x + 25 - (3x² + 12x - 5x - 20)
= 9x^2 - 3x^2 - 30x - 7x + 25 + 20
= 6x^2 - 37x + 45
b) (3x-5) [ (3x-5)-(x+4) ]
= (3x-5) (3x-5 - x - 4)
= (3x-5) (2x - 9)
c) Quand x = 1
(3 * 1 - 5) (2 * 1 - 9)
= (3-5) (2 - 9)
= -2 x -7
= 14
quand x=4.5
= (13.5 -5 ) (9-9)
=8.5 * 0
= 0
1 votes
Thanks 0
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Verified answer
Bonjour,a) (3x-5)^2 - (3x-5) (x+4)
= 9x² -30x + 25 - (3x² + 12x - 5x - 20)
= 9x^2 - 3x^2 - 30x - 7x + 25 + 20
= 6x^2 - 37x + 45
b) (3x-5) [ (3x-5)-(x+4) ]
= (3x-5) (3x-5 - x - 4)
= (3x-5) (2x - 9)
c) Quand x = 1
(3 * 1 - 5) (2 * 1 - 9)
= (3-5) (2 - 9)
= -2 x -7
= 14
quand x=4.5
= (13.5 -5 ) (9-9)
=8.5 * 0
= 0