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jaruaba20
@jaruaba20
October 2020
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A soma dos termos de uma PA, que possui 13 termos e razão 4, vale 39. Determine o valor do oitavo termo.
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sarajesuina
An=a1+(n-1)r
a13=a1+(13-1)r
39=a1+12r
39=a1+12*4
39=a1+48
a1=39-48
a1=-9
an=a1+(n-1)r
a8=a1+(8-1)r
a8=-9+7r
a8=-9+7*4=-9+28=19
a8=19
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a13=a1+(13-1)r
39=a1+12r
39=a1+12*4
39=a1+48
a1=39-48
a1=-9
an=a1+(n-1)r
a8=a1+(8-1)r
a8=-9+7r
a8=-9+7*4=-9+28=19
a8=19