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lea7
@lea7
June 2021
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aider moi pour demain!!
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thomasbougeon
1) Pour les valeurs de x entre -2 et 2
2) f(-1) = 2
f(0) = 0
f(1) = -2
f(x) = 2 alors x = -1 et 2 (donc 2 antécédents)
f(x) =-2 alors x = 1 et -2 (donc 2 antécédents)
3)f(-1/2) = (-1/2)^3-3*1/2 = -1/8 -3/2 = -13/8
f(1/2) = 13/8 (c'est une fonction impaire)
f(2) = 2^3-3*2 = 8-6 = 2 donc A(2;2) est bien un point de la courbe
Voila !
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Bonjour je sais que pour calculer un vitesse c'est distance diviser par temps : v= d:t Et je voudrais savoir comment calculer un distance ? W... Svp :)
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juste la question 2 s'il vous plait :) (les tarif sont expliquer dans la 2eme piece jointe )
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2) f(-1) = 2
f(0) = 0
f(1) = -2
f(x) = 2 alors x = -1 et 2 (donc 2 antécédents)
f(x) =-2 alors x = 1 et -2 (donc 2 antécédents)
3)f(-1/2) = (-1/2)^3-3*1/2 = -1/8 -3/2 = -13/8
f(1/2) = 13/8 (c'est une fonction impaire)
f(2) = 2^3-3*2 = 8-6 = 2 donc A(2;2) est bien un point de la courbe
Voila !