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lea7
@lea7
June 2021
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Aider moi silvouplait devoir noter !:) pour l'exercice 2 au dessus de chaque puissance je l'ai réécrit au crayon parcque on voyait pas bien merci d'avance !
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Exercice 2
1) 2^1 se lit 2 puissance 1
2^1+2^1 = 2+2 = 4 = 2^2
2^2+2^2 = 4+4 = 8 = 2*2^2 = 2^3
2^3+2^3 = 8+8 = 16 = 2*2^3 = 2^4
2^4+2^4 = 16+16 = 32 = 2*2^4 = 2^5
2^-1 +2^-1 = 0.5+0.5 = 1 = 2^0
2^-2+2^-2 = 0.25+0.25 = 0.5 = 2^-1
2) Si n est un entier il semble que 2^n + 2^n = 2^(n+1)
Démonstration
2^n + 2^n = 1*2^n + 1*2^n = (1+1)2^n = 2*2^n = 2^1*2^n = 2^(n+1)
3) 3^n +3^n = 1*3^n + 1*3^n = (1+1)3^n = 2*3^n différent de 3^(n+1)
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juste la question 2 s'il vous plait :) (les tarif sont expliquer dans la 2eme piece jointe )
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1) 2^1 se lit 2 puissance 1
2^1+2^1 = 2+2 = 4 = 2^2
2^2+2^2 = 4+4 = 8 = 2*2^2 = 2^3
2^3+2^3 = 8+8 = 16 = 2*2^3 = 2^4
2^4+2^4 = 16+16 = 32 = 2*2^4 = 2^5
2^-1 +2^-1 = 0.5+0.5 = 1 = 2^0
2^-2+2^-2 = 0.25+0.25 = 0.5 = 2^-1
2) Si n est un entier il semble que 2^n + 2^n = 2^(n+1)
Démonstration
2^n + 2^n = 1*2^n + 1*2^n = (1+1)2^n = 2*2^n = 2^1*2^n = 2^(n+1)
3) 3^n +3^n = 1*3^n + 1*3^n = (1+1)3^n = 2*3^n différent de 3^(n+1)