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Jenni0901
@Jenni0901
January 2021
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Aider moi stp je n’y arrive pas
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aur70
Bonjour
A(x)=1-4x²-(1-2x)(2+x)
1/ A(x)=1-4x²-(2+x-4x-2x²)=1-4x²-(2-3x-2x²)=1-4x²-2+3x+2x²=-2x²+3x-1
2/ A(x)=1-4x²-(1-2x)(2+x)=1²-(2x)²-(1-2x)(2+x)=(1-2x)(1+2x)-(1-2x)(2+x)
A(x)=(1-2x)(1+2x-2-x)=(1-2x)(-1+x)
3/ a/ A(x)=0 ⇔ (1-2x)(-1+x)=0
b/ A(x)=-1 ⇔ 1-4x²-(1-2x)(2+x)=-1 ⇔ -4x²-(1-2x)(2+x)=0
c/ A(x)=3x-1 ⇔(1-2x)(-1+x)=3x-1 ⇔-2x²=0
4/ A(0)=(1-2*0)(-1+0)=1*(-1)=-1
A(√3)=(1-2√3)(-1+√3)=-1+√3+2√3-6=-7+3√3
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Jenni0901
Merci bcp
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A(x)=1-4x²-(1-2x)(2+x)
1/ A(x)=1-4x²-(2+x-4x-2x²)=1-4x²-(2-3x-2x²)=1-4x²-2+3x+2x²=-2x²+3x-1
2/ A(x)=1-4x²-(1-2x)(2+x)=1²-(2x)²-(1-2x)(2+x)=(1-2x)(1+2x)-(1-2x)(2+x)
A(x)=(1-2x)(1+2x-2-x)=(1-2x)(-1+x)
3/ a/ A(x)=0 ⇔ (1-2x)(-1+x)=0
b/ A(x)=-1 ⇔ 1-4x²-(1-2x)(2+x)=-1 ⇔ -4x²-(1-2x)(2+x)=0
c/ A(x)=3x-1 ⇔(1-2x)(-1+x)=3x-1 ⇔-2x²=0
4/ A(0)=(1-2*0)(-1+0)=1*(-1)=-1
A(√3)=(1-2√3)(-1+√3)=-1+√3+2√3-6=-7+3√3