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Jenni0901
@Jenni0901
January 2021
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Bonjour je suis un peu bloquer sur cette exo 108 je sais que il faut utiliser la trigonométrie mais je ne sais pas comment aider moi stp...
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trudelmichel
Verified answer
Bonjour,
distance parcourue en 45s
45s=3/4mn=3/4x60=3x1/4x20x3=1/80=0.0125h
noued=1.852km/h
1.852x0.0125=0.02315km=23.15m
triangle rectangle FAH
tangent A=FH/AH
tangente 25°=0.466
0.466=FH/AH
FH=0.466 x AH
triangle rectangle FBH
tangente B=FH/BH
tangente 60°=1.732
1.732=FH/BH
FH=1.732 x BH
0.466 x AH=1.732 x BH
BH=AH-AB
BH=AH-23.15
0.466 x AH= 1.732(AH-23.15)
0.466 x AH = (1.732 x AH) - (1.732 x 23.15)
0.446 AH=1.732 AH-40.09
40.09=1.732 AH-0.446AH
40.09=1.266 AH
AH= 40.09/1.266
AH=31.67 (arrondi au 1/100)
tangente A=FH/AH
tangnet 25°=0.466
0.466=FH/31.67
FH= 0.466 x 31.67
FH=14.75
la falaise a une hauteur de 14.75 m
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Jenni0901
Merci bcp de votre aider
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Lista de comentários
Verified answer
Bonjour,distance parcourue en 45s
45s=3/4mn=3/4x60=3x1/4x20x3=1/80=0.0125h
noued=1.852km/h
1.852x0.0125=0.02315km=23.15m
triangle rectangle FAH
tangent A=FH/AH
tangente 25°=0.466
0.466=FH/AH
FH=0.466 x AH
triangle rectangle FBH
tangente B=FH/BH
tangente 60°=1.732
1.732=FH/BH
FH=1.732 x BH
0.466 x AH=1.732 x BH
BH=AH-AB
BH=AH-23.15
0.466 x AH= 1.732(AH-23.15)
0.466 x AH = (1.732 x AH) - (1.732 x 23.15)
0.446 AH=1.732 AH-40.09
40.09=1.732 AH-0.446AH
40.09=1.266 AH
AH= 40.09/1.266
AH=31.67 (arrondi au 1/100)
tangente A=FH/AH
tangnet 25°=0.466
0.466=FH/31.67
FH= 0.466 x 31.67
FH=14.75
la falaise a une hauteur de 14.75 m