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Reem
@Reem
April 2019
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Aider moi svp c'est pour demain !!! Merci d'avance
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senmusa
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Question 1 : f(x) = x² -2x -3
question 2 : f(x) = (x - 3)(x+1) = x² + x - 3x - 3 = x² -2x - 3
et f(x) = (x-1)²-4 = x² + 1 - 2x - 4 = x² -2x - 3
question 3 : la première forme donne directement les solutions. On souhaite f(x) = 0 ===> f(x) = (x-3)(x+1) = 0 x= 3 ou x = -1 ===> Sol = { -1 ; 3 }
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senmusa
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Verified answer
Question 1 : f(x) = x² -2x -3question 2 : f(x) = (x - 3)(x+1) = x² + x - 3x - 3 = x² -2x - 3
et f(x) = (x-1)²-4 = x² + 1 - 2x - 4 = x² -2x - 3
question 3 : la première forme donne directement les solutions. On souhaite f(x) = 0 ===> f(x) = (x-3)(x+1) = 0 x= 3 ou x = -1 ===> Sol = { -1 ; 3 }