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lucasmartin78lm
@lucasmartin78lm
December 2020
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Aidez-moi s'il vous plaît pour cet exercice
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vieiraclara152
1: (AB=1/BC=1/CD=1/DE=2/EF=2 et FA=3)
Donc
P= AB+BC+CD+DE+EF+FA
P=1+1+1+2+2+3
P= 10
2:
P=AB+BC+CD+DE+EA+EB
P= 1,4+2+2+2+1,4+2
P=10,8
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Donc
P= AB+BC+CD+DE+EF+FA
P=1+1+1+2+2+3
P= 10
2:
P=AB+BC+CD+DE+EA+EB
P= 1,4+2+2+2+1,4+2
P=10,8