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Manondetoulouse
@Manondetoulouse
April 2019
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AIDEZ-MOI S'IL VOUS PLAÎT !
Résoudre les équations suivantes à l'aide de la factorisation :
• x² - 1 = (x + 1)
• 9x² - 1 = (3x-1)(2x + 5)
Merci de votre aide.
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Bonjour
x² - 1 = (x + 1)
(x+1)(x-1)=
(x + 1)
(x+1)(x-1)-(x + 1)=0
(x+1)(x-1-1)=0
(x+1)(x-2)=0
x=-1 ou x=2
9x² - 1 = (3x-1)(2x + 5)
(3x-1)(3x+1)=
(3x-1)(2x + 5)
(3x-1)(3x+1)-(3x-1)(2x + 5)=0
(3x-1)(3x+1-2x-5)=0
(3x-1)(x-4)=0
x=1/3 ou x=4
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Lista de comentários
x² - 1 = (x + 1)
(x+1)(x-1)=(x + 1)
(x+1)(x-1)-(x + 1)=0
(x+1)(x-1-1)=0
(x+1)(x-2)=0
x=-1 ou x=2
9x² - 1 = (3x-1)(2x + 5)
(3x-1)(3x+1)=(3x-1)(2x + 5)
(3x-1)(3x+1)-(3x-1)(2x + 5)=0
(3x-1)(3x+1-2x-5)=0
(3x-1)(x-4)=0
x=1/3 ou x=4