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Elodiepo44
@Elodiepo44
April 2019
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AIDEZ MOI SVP TROP DURE !!!
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clemelle
1-
(390 x 1012) / (5 x 109
)
= (390/5)x(1012/109
)
= (78) x (103
)
= 78000 !
Il faut donc 78 000 éoliennes pour remplacer les centrales nucléaires
2-
sachant que 1 KWh = 103
Wh
390 x 1012
/ (160 Wh x 10
3
= (390/160) x (1012
/ 10
3
)
= (2,43) x (109
)
= 2430000000 m2
= 2430 km2
Il faudrait 2430 km2 de photovoltaïque pour remplacer les centrales nucléaires.
1 votes
Thanks 1
elodiepo44
merci beaucoup !!
clemelle
De rien
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Lista de comentários
= (390/5)x(1012/109)
= (78) x (103)
= 78000 !
Il faut donc 78 000 éoliennes pour remplacer les centrales nucléaires
2- sachant que 1 KWh = 103 Wh
390 x 1012 / (160 Wh x 103
= (390/160) x (1012 / 10 3)
= (2,43) x (109)
= 2430000000 m2
= 2430 km2
Il faudrait 2430 km2 de photovoltaïque pour remplacer les centrales nucléaires.