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elodiepo44
@elodiepo44
January 2021
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J'ai besoin d'aide svp c'est chaud :'(
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caylus
Verified answer
Bonjour,
Soit x la distance AM.
1)
Aire ADM=50*x/2
Aire BCM=30*(70-x)/2
50x=30(70-x)
=>50x+30x=2100
=>x=105/4=26.25
2)
|DM|=√(50²+x²)
|MC|=√(30²+(70-x)²)
=>50²+x²=30²+(70-x)²
=>2500=900+4900-140x
=>140x=3300
=>x=165/7=23.571428 571428 571428 ....
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Lista de comentários
Verified answer
Bonjour,Soit x la distance AM.
1)
Aire ADM=50*x/2
Aire BCM=30*(70-x)/2
50x=30(70-x)
=>50x+30x=2100
=>x=105/4=26.25
2)
|DM|=√(50²+x²)
|MC|=√(30²+(70-x)²)
=>50²+x²=30²+(70-x)²
=>2500=900+4900-140x
=>140x=3300
=>x=165/7=23.571428 571428 571428 ....