j) [tex](-\frac{4}{9}) . \frac{1}{2} = (-\frac{4}{18} )[/tex]
Resposta:
j)
[tex](-\dfrac{\not4^2}{9})\times\dfrac{1}{\not2}=-\dfrac{2}{9}[/tex]
k)
[tex](+\dfrac{5}{\not4})\times(-\dfrac{\not4}{11})=-\dfrac{5}{11}[/tex]
l)
[tex](+\dfrac{6}{10})\times(-\dfrac{1}{3})=-\dfrac{6}{30}=-\dfrac{1}{5}[/tex]
m)
calcula cancelando
[tex](-\dfrac{\not7}{\not2})\times(+\dfrac{\not3}{\not14_2})\times(-\dfrac{\not2}{\not3})=+\dfrac{1}{2}[/tex]
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Resposta:
j) [tex](-\frac{4}{9}) . \frac{1}{2} = (-\frac{4}{18} )[/tex]
Resposta:
j)
[tex](-\dfrac{\not4^2}{9})\times\dfrac{1}{\not2}=-\dfrac{2}{9}[/tex]
k)
[tex](+\dfrac{5}{\not4})\times(-\dfrac{\not4}{11})=-\dfrac{5}{11}[/tex]
l)
[tex](+\dfrac{6}{10})\times(-\dfrac{1}{3})=-\dfrac{6}{30}=-\dfrac{1}{5}[/tex]
m)
calcula cancelando
[tex](-\dfrac{\not7}{\not2})\times(+\dfrac{\not3}{\not14_2})\times(-\dfrac{\not2}{\not3})=+\dfrac{1}{2}[/tex]