Resposta:

Letra D

Explicação passo a passo:

[tex]\sqrt[3]{\dfrac{14}{125}+\sqrt{\dfrac{3}{5}-\dfrac{11}{25}} } =\\ \\ \\ \sqrt[3]{\dfrac{14}{125}+\sqrt{\dfrac{15-11}{25}} } =\\ \\ \\ \sqrt[3]{\dfrac{14}{125}+\sqrt{\dfrac{4}{25}} } =\\ \\ \\ \sqrt[3]{\dfrac{14}{125}+\dfrac{2}{5}} =\\ \\ \\ \sqrt[3]{\dfrac{14+50}{125}} =\\ \\ \\ \sqrt[3]{\dfrac{64}{125}} =\sqrt[3]{\dfrac{4^3}{5^3}} =\boxed{\dfrac{4}{5}}[/tex]