Verified answer

Efetuados os cálculos pelo Teorema de Pitágoras os resultados obtidos

foram

[tex]a) 35\\b) 7[/tex]

[tex]c)\\[/tex] [tex]4\sqrt{6}\\[/tex]

[tex]d)\\[/tex] [tex]2\sqrt{5} \\[/tex]

[tex]e) 2\\f) 40[/tex]

Aplicando-se o Teorema de Pitágoras temos:

[tex]a) x^2 = 21^2 + 28^2\\x^2 = 441 + 784\\x^2 = 1225\\x = \sqrt{1225}\\ x = 35\\[/tex]

[tex]b) 25^2 = x^2 + 24^2\\625 = x^2 + 576\\x^2 = 625 - 576\\x^2 = 49\\x = \sqrt{49}\\x = 7\\[/tex]

[tex]c) 11^2 = x^2 + 5^2\\121 = x^2 + 25\\x^2 = 121 - 25\\x^2 = 96\\x = \sqrt{96}\\x = \sqrt{16.6}\\x = 4\sqrt{6}\\ \\d) \sqrt{50}^2 = \sqrt{30}^2 + x^2 \\50 = 30 + x^2\\x^2 = 50 - 30\\x^2 = 20\\x = \sqrt{20}\\x = \sqrt{4.5}\\x = 2\sqrt{5}\\\\e) \sqrt{29}^2 = x^2 + 5^2\\ 29 = x^2 + 25\\x^2 = 29 - 25\\x^2 = 4\\x = \sqrt{4}\\ x = 2\\\\f) x^2 = 24^2 + 32^2\\x^2 = 576 + 1024\\x^2 = 1600\\x = \sqrt{1600}\\x = 40\\\\[/tex]

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