Explications étape par étape :
x² - 3x + 2 = 0
a = 1
b = -3
c = 2
Δ = (-3)² - 4 × 1 × 2
⇔ Δ = 9 - 8
⇔ Δ = 1
Δ > 0, 2 solutions:
x₁ = [- (- 3) - √1 ] / ( 2 × 1 ) = ( 3 - 1 ) / 2 = 2/2 = 1
x₂ = [- (- 3) + √1 ] / ( 2 × 1 ) = ( 3 + 1 ) / 2 = 4/2 = 2
S = { 1 ; 2 }
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Explications étape par étape :
x² - 3x + 2 = 0
a = 1
b = -3
c = 2
Δ = (-3)² - 4 × 1 × 2
⇔ Δ = 9 - 8
⇔ Δ = 1
Δ > 0, 2 solutions:
x₁ = [- (- 3) - √1 ] / ( 2 × 1 ) = ( 3 - 1 ) / 2 = 2/2 = 1
x₂ = [- (- 3) + √1 ] / ( 2 × 1 ) = ( 3 + 1 ) / 2 = 4/2 = 2
S = { 1 ; 2 }