A(x) = (x + 1)(3 - 2x) + 2(2x² - 9)
= 3x - 2x² +3 - 2x + 4x² - 18
= 2x² + x - 15
B(x) = 2x(x + 3) - 5(x + 3)
= (x + 3)(2x - 5)
Démontrer A(x) = B(x)
A partir de B(x) = (x + 3)(2x - 5)
= 2x² - 5x + 6x - 15
donc B(x) = A(x) = 2x² + x - 15
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Verified answer
A(x) = (x + 1)(3 - 2x) + 2(2x² - 9)
= 3x - 2x² +3 - 2x + 4x² - 18
= 2x² + x - 15
B(x) = 2x(x + 3) - 5(x + 3)
= (x + 3)(2x - 5)
Démontrer A(x) = B(x)
A partir de B(x) = (x + 3)(2x - 5)
= 2x² - 5x + 6x - 15
= 2x² + x - 15
donc B(x) = A(x) = 2x² + x - 15