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Salut437
@Salut437
April 2019
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Bonjour à tous !
J'aimerais savoir si le résultat à ma factorisation est correct. Merci d'avance !
A = 4x²-4x+1+(2x-1)(x-3)
= (2x+1)²+(2x+1)(x+3)
=(2x+1)(2x+1)+(2x+1)(x+3)
=(2x+1) [(2x+1)(x+3)]
=(2x+1)(2x+1+x+3)
=(2x+1)(3x+4)
Je pense que mon est faux, mais merci d'avance !
PS : N'existe-t-il pas une méthode permettant de savoir si le résultat d'une factorisation est bon ?
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nonotata
Bonjour,
A = 4x²-4x+1+(2x-1)(x-3)
= (2x+1)²+(2x+1)(x+3) faux 4x²-4x+1 =(2x-1)²
=(2x+1)(2x+1)+(2x+1)(x+3)
=(2x+1) [(2x+1)(x+3)]
=(2x+1)(2x+1+x+3)
=(2x+1)(3x+4)
donc
a =
A = 4x²-4x+1+(2x-1)(x-3)
= (2x-1)²+(2x-1)(x-3)
=(2x-1)(2x-1)+(2x-1)(x-3)
=(2x-1)(2x-1+x-3)
=(2x-1)(3x-4)
2 votes
Thanks 1
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A = 4x²-4x+1+(2x-1)(x-3)
= (2x+1)²+(2x+1)(x+3) faux 4x²-4x+1 =(2x-1)²
=(2x+1)(2x+1)+(2x+1)(x+3)
=(2x+1) [(2x+1)(x+3)]
=(2x+1)(2x+1+x+3)
=(2x+1)(3x+4)
donc
a =A = 4x²-4x+1+(2x-1)(x-3)
= (2x-1)²+(2x-1)(x-3)
=(2x-1)(2x-1)+(2x-1)(x-3)
=(2x-1)(2x-1+x-3)
=(2x-1)(3x-4)