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Oceane2508
@Oceane2508
April 2019
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Bonjour à tous, quelqu'un peut- il m'aider à factoriser cette expression svp :) a(x)= (2x+3)²-(x-1)²
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alpha333
Il s'agit d'une identité remarquable.
A(x)= (2x+3)²-(x-1)²
=[(2x+3)+(x-1)][(2x+3)-(x-1)]
=(2x+3+x-1) (2x+3-x+1)
=(3x+2) (x+4)
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A(x)= (2x+3)²-(x-1)²
=[(2x+3)+(x-1)][(2x+3)-(x-1)]
=(2x+3+x-1) (2x+3-x+1)
=(3x+2) (x+4)