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May 2019
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Bonjour, aider moi svp
On tire au hasard dans un jeu de 32 cartes
1) calculer la probabilité que ca soit un coeur ou une figure.
2) Calculer la probabilité que ca soit ni un coeur ni une figure .
je ne comprend pas comment faire
Merci en avance de votre aide
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trudelmichel
Verified answer
Bonjour,
a)
P(coeur ou figure)=P(coeur ∪ figure)
P(coeur ∪ figure)=P(coeur)+P(figure)-P(coeur ∩ figure )
b)
P(coeur)
8 coeurs pour 32 cartes
P(coeur)=8/32=1/4=0.25
c)
P(figure)
12 figures
P(figure)=12/32=0.375
d)
P(coeur ∩ figure)
3 figures coeur
P(coeur ∩ figure)=3/32=0.093
e)
P(coeur ∪ figure)= 0.25+0.375-0.093
P(coeur ∪ figure)=0.532
f)
(coeur ou figure) et(ni coeur ni figure) sont des évènements contraires
P(coeur ou figure)+P(ni coeur ni figure)=1
P(ni coeur ni figure)=1-0.532=0.468
2 votes
Thanks 1
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Lista de comentários
Verified answer
Bonjour,a)
P(coeur ou figure)=P(coeur ∪ figure)
P(coeur ∪ figure)=P(coeur)+P(figure)-P(coeur ∩ figure )
b)
P(coeur)
8 coeurs pour 32 cartes
P(coeur)=8/32=1/4=0.25
c)
P(figure)
12 figures
P(figure)=12/32=0.375
d)
P(coeur ∩ figure)
3 figures coeur
P(coeur ∩ figure)=3/32=0.093
e)
P(coeur ∪ figure)= 0.25+0.375-0.093
P(coeur ∪ figure)=0.532
f)
(coeur ou figure) et(ni coeur ni figure) sont des évènements contraires
P(coeur ou figure)+P(ni coeur ni figure)=1
P(ni coeur ni figure)=1-0.532=0.468