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Jellal252827
@Jellal252827
April 2019
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Bonjour c'est urgent aider moi pour l'exercice 44 c'est pour demain aider moi en urgence
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IA=|Za-Zi|=|1+i√3-(-3/2+i√3/2)|=|5/2+i√3/2|=√(25/4+3/4)=√7
IB=|Zb-Zi|=|-2+i2√3-(-3/2+i√3/2)|=|-1/2+i3√3/2|=√(1/4+27/4)=√7
IC=|Zc-Zi|=|-1-i√3-(-3/2+i√3/2)|=|1/2-3i√3/2|=√(1/4+27/4)=√7
ID=|Zd-Zi|=|1/2-i√3/2-(-3/2+i√3/2)|=|2-i√3|=√(4+3)=√7
donc A,B,C,D ∈ Cercle(I;√7)
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IB=|Zb-Zi|=|-2+i2√3-(-3/2+i√3/2)|=|-1/2+i3√3/2|=√(1/4+27/4)=√7
IC=|Zc-Zi|=|-1-i√3-(-3/2+i√3/2)|=|1/2-3i√3/2|=√(1/4+27/4)=√7
ID=|Zd-Zi|=|1/2-i√3/2-(-3/2+i√3/2)|=|2-i√3|=√(4+3)=√7
donc A,B,C,D ∈ Cercle(I;√7)