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clarafiona
@clarafiona
June 2021
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Bonjour, devoir pour demain avec étapes intermédiaires :
Factoriser :
a. 4x² + 4x + 4
b. -5x² + 10x + 15
c. 9y² - 3y + 27
d. 3y³ + y²
je donne beaucoup de points !!
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jujumy
A) 4x²+4x+4 = (2x+2)² ou 4(x²+x+1)
b) -5x²+10x+15 = -5(x-3)(x+1)
c) 9y²-3y+27 = 3(3y²-y+9)
d) 3y^3 +y² = y²(3y+1)
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nathalienouts
A. 4x² + 4x + 4
4(x²+x+1)
4[x(x+1)+1]
b. -5x² + 10x + 15
=5(-x²+2x+3)
=5[x(-x+2)+3]
c. 9y² - 3y + 27
=3(3y²-y+9)
=3[y(3y-1)+9]
d. 3y³ + y²
=4y
²
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Lista de comentários
b) -5x²+10x+15 = -5(x-3)(x+1)
c) 9y²-3y+27 = 3(3y²-y+9)
d) 3y^3 +y² = y²(3y+1)
4(x²+x+1)
4[x(x+1)+1]
b. -5x² + 10x + 15
=5(-x²+2x+3)
=5[x(-x+2)+3]
c. 9y² - 3y + 27
=3(3y²-y+9)
=3[y(3y-1)+9]
d. 3y³ + y²
=4y²