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saib976
@saib976
January 2021
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Bonjour est ce que vous pourrrez m'aidez a factorisé: (2x-4)²-(x-1)²
merci d'avance
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tsapos
Bonjour :
(2x - 4)² - (x - 1)²
(2x - 4)² - (x - 1)² il prend la forme de a²-b² = (a - b)(a+b)
Alors :
[(2x - 4) - (x - 1)][(2x - 4) + (x - 1)]
(2x - 4 - x + 1)(2x - 4 + x - 1)
(2x - x - 4 + 1)(2x + x - 4 - 1)
(x - 3)(3x - 5)
J’espère t'avoir t'aider
1 votes
Thanks 1
saib976
merci beaucoup
nini999
Verified answer
On sait que a²-b² = (a-b)×(a+b)
Donc (2x-4)²-(x-1)² = (2x-4-(x-1))×(2x-4+(x-1)) = (2x-4-x+1)×(2x-4+x-1) = (x-3)×(3x-5)
2 votes
Thanks 1
saib976
he bien tu ma bien aider mrc
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Lista de comentários
(2x - 4)² - (x - 1)²
(2x - 4)² - (x - 1)² il prend la forme de a²-b² = (a - b)(a+b)
Alors :
[(2x - 4) - (x - 1)][(2x - 4) + (x - 1)]
(2x - 4 - x + 1)(2x - 4 + x - 1)
(2x - x - 4 + 1)(2x + x - 4 - 1)
(x - 3)(3x - 5)
J’espère t'avoir t'aider
Verified answer
On sait que a²-b² = (a-b)×(a+b)Donc (2x-4)²-(x-1)² = (2x-4-(x-1))×(2x-4+(x-1)) = (2x-4-x+1)×(2x-4+x-1) = (x-3)×(3x-5)