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Mav31
@Mav31
May 2019
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Bonjour, étant en classe de 2nde, j'ai un DM de maths à faire et pour une fois j'ai tout réussi mais il manque ça :
Factoriser l'expression :
(2x-1)(3x+6)-(x+1)(x+2)
Merci!
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swnn
(2x-1)(3x+6)-(x+1)(x+2)
→ (3x+6) = 3(x+2)
donc (x+2) est le facteur commun
3(2x-1)(x+2)-(x+1)(x+2)
= (x+2)[3(2x-1)-(x+1)]
= (x+2)(6x-3-x-1)
= (x+2)(5x-4)
1 votes
Thanks 1
mav31
Merci Swnn!
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→ (3x+6) = 3(x+2)
donc (x+2) est le facteur commun
3(2x-1)(x+2)-(x+1)(x+2)
= (x+2)[3(2x-1)-(x+1)]
= (x+2)(6x-3-x-1)
= (x+2)(5x-4)