Bonjour factorisation d'expression bonne chance '-'
15x-12
5x-5
6x²+10x
(3x+2)(4x-1)+(3x+2)(-6x+8)
(3x-4)²-(2x-5)(3x-4)
(2x-3)²-(2x-3)
15x-12
5x-5
6x²+10x
(3x+2)(4x-1)+(3x+2)(-6x+8)
(3x-4)²-(2x-5)(3x-4)
(2x-3)²-(2x-3)
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Verified answer
15x-12 = 3*(5x-4)5x-5 = 5*(x-1)
6x²+10x = 2x*(3x+5)
(3x+2)(4x-1)+(3x+2)(-6x+8)
= (3x+2)[(4x-1)+(-6x+8)]
= (3x+2)(4x-1-6x+8)
= (3x+2)(-2x+7)
(3x-4)²-(2x-5)(3x-4)
= (3x-4)[(3x-4)-(2x-5)]
= (3x-4)(3x-4-2x+5)
= (3x-4)(x+1)
(2x-3)²-(2x-3)
= (2x-3)[(2x-3)-1]
= (2x-3)(2x-3-1)
= (2x-3)(2x-4)