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Sanathys
@Sanathys
April 2019
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Bonjour,
j ai encore besoin de vous s il vous plaît.
je vous joints mon dm.
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slyz007
Verified answer
Soit x et y les dimensions manquantes avec y l'hypoténuse.
On sait que 15+x+y=90
et que 15²+x²=y²
On en déduit que y=90-15-x=75-x
Donc y²=(75-x)²=5625-150x+x²
On a donc 15²+x²=5625-150x+x²
Donc 150x=5625-15²+x²-x²=5400
donc x=36
et y=75-36=39
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Lista de comentários
Verified answer
Soit x et y les dimensions manquantes avec y l'hypoténuse.On sait que 15+x+y=90
et que 15²+x²=y²
On en déduit que y=90-15-x=75-x
Donc y²=(75-x)²=5625-150x+x²
On a donc 15²+x²=5625-150x+x²
Donc 150x=5625-15²+x²-x²=5400
donc x=36
et y=75-36=39