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lisa49570
@lisa49570
January 2021
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Bonjour , j'ai besoin de pistes pour cet exercice, car je souhaite faire du thalès mais il me manque toujours une longueur , pourriez vous m'aidez ?
Merci d'avance
bonne soirée
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AhYan
Verified answer
Angle DFM= 180°- angle MFG = 180-120=60°
Sin (60°)= DM/MF
==> MF=DM/Sin(60°)=8,2/sin(60)
Avec Thales, on a
MF/GA=DM/MA=DF/DG
=> GA= (MF×MA)/DM
DMF est un triangle rectangle, donc selon Pythagore, on a:
FM^2=DM^2+DF^2
donc DF^2=FM^2-DM^2
DF=√(FM^2-DM^2)
DG=(DF×MA)/DM
FG=DG-DF
1 votes
Thanks 0
lisa49570
je te remercie beaucoup :)
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Lista de comentários
Verified answer
Angle DFM= 180°- angle MFG = 180-120=60°Sin (60°)= DM/MF
==> MF=DM/Sin(60°)=8,2/sin(60)
Avec Thales, on a
MF/GA=DM/MA=DF/DG
=> GA= (MF×MA)/DM
DMF est un triangle rectangle, donc selon Pythagore, on a:
FM^2=DM^2+DF^2
donc DF^2=FM^2-DM^2
DF=√(FM^2-DM^2)
DG=(DF×MA)/DM
FG=DG-DF