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Bonjour,

Attribuer sa forme canonique :

f(x) = x^2 + 4x + 1

g(x) = x^2 - 6x - 5

h(x) = x^2 + 12x + 36

K(x) = x^2 - 2x + 3

A = (x + 6)^2 = x^2 + 12x + 36 = h(x)

B = (x - 1)^2 + 2 = x^2 - 2x + 1 + 2 = x^2 - 2x + 3 = k(x)

C = (x - 3)^2 - 14 = x^2 - 6x + 9 - 14 = x^2 - 6x - 5 = g(x)

D = (x + 2)^2 - 3 = x^2 + 4x + 4 - 3 = x^2 + 4x + 1 = f(x)

Exercice 5 :

f(x) = 2x^2 + 12x - 5

G(x) = -x^2 - 2x + 5

H(x) = -x^2 + 2x + 16

K(x) = x^2 + 8x

A = (x + 4)^2 - 16 = x^2 + 8x + 16 - 16 = x^2 + 8x = k(x)

B = -(x - 1)^2 + 17 = -(x^2 - 2x + 1) + 17 = -x^2 + 2x - 1 + 17 = -x^2 + 2x + 16 = h(x)

C = 2(x + 3)^2 - 23 = 2(x^2 + 6x + 9) - 23 = 2x^2 + 12x + 18 - 23 = 2x^2 + 12x - 5 = f(x)

D = -(x + 1)^2 + 6 = -(x^2 + 2x + 1) + 6 = -x^2 - 2x - 1 + 6 = -x^2 - 2x + 5 = g(x)