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Liorasarah
@Liorasarah
May 2019
2
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Bonjour, j'ai du mal sur cette question :
Vérifier que pour tout x ≠ 1,
Je vous remercie !
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trudelmichel
Verified answer
Bonjour
[(2x-1)/(x+1)]+2= [(2x-1)/(x+1)]+[2(x+1)/x+1)]
[(2x-1)+2(x+1)]/x+1=([(2x-1)+(2x+2)]/x+1
(2x-1+2x+2)/x+1 = 4x+1/x+1
1 votes
Thanks 1
Liorasarah
Merci ! :)
nini999
Verified answer
Bonjour :
(2x - 1)/(x + 1) + 2 = (4x + 1)/(x + 1)
(2x - 1)/
(x + 1)
+ 2(x + 1)/
(x + 1)
= (4x + 1)/
(x + 1)
(2x - 1) + 2(x + 1) = (4x + 1)
(2x - 1) + (2x + 2) = (4x + 1)
2x - 1 + 2x + 2 = 4x + 1
2x + 2x - 1 + 2 = 4x + 1
4x + 1 = 4x + 1
4x + 1 - 4x - 1 = 0
4x - 4x + 1 - 1 = 0
0 = 0
il y a pas une solution pour cette équation
J’espère t'avoir t'aider
0 votes
Thanks 0
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Lista de comentários
Verified answer
Bonjour[(2x-1)/(x+1)]+2= [(2x-1)/(x+1)]+[2(x+1)/x+1)]
[(2x-1)+2(x+1)]/x+1=([(2x-1)+(2x+2)]/x+1
(2x-1+2x+2)/x+1 = 4x+1/x+1
Verified answer
Bonjour :(2x - 1)/(x + 1) + 2 = (4x + 1)/(x + 1)
(2x - 1)/(x + 1) + 2(x + 1)/(x + 1) = (4x + 1)/(x + 1)
(2x - 1) + 2(x + 1) = (4x + 1)
(2x - 1) + (2x + 2) = (4x + 1)
2x - 1 + 2x + 2 = 4x + 1
2x + 2x - 1 + 2 = 4x + 1
4x + 1 = 4x + 1
4x + 1 - 4x - 1 = 0
4x - 4x + 1 - 1 = 0
0 = 0
il y a pas une solution pour cette équation
J’espère t'avoir t'aider