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Mariedu94
@Mariedu94
April 2019
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Bonjour,
J'ai un devoir de maths à faire et je bloque sur le dernière exercice où je dois factoriser.
A=(x+1)(x+2)+5(x+2)
=(x+2)[(x+1)+5]
=(x+2)(x+1+5)
=(x+2)(x+6)
B=(2x+1)²-(2x+1)(x+3)
=(2x+1)(2x+1)-(2x+1)(x+3)
=(2x+1)[2x+1)-(x+3)
=(2x+1)(x-2)
C=(2x-5)²-x²
D=8x²-5x
Pour la D et la C je bloque. En espérant avoir un réponde avec des explications. Merci :)
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ficanas06
Verified answer
C=(2x-5)² - x² du type a²-b²=(a+b)(a-b)
C= (2x-5+x)(2x-5-x)
C= (3x-5)(x-5)
D= x(8x-5)
3 votes
Thanks 2
Mariedu94
Merci !!! Mais comment tu trouve D= x(8x-5) ?
ficanas06
le facteur commun est x dans (8x²-5x)
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Bonsoir, J'aurais besoin d'aide pour la question (le a, b et c). Si vous avez besoin d'infomation sur question d'avant demandez moi. Merci d'avance !
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Verified answer
C=(2x-5)² - x² du type a²-b²=(a+b)(a-b)C= (2x-5+x)(2x-5-x)
C= (3x-5)(x-5)
D= x(8x-5)