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Math0fanny
@Math0fanny
April 2019
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Bonjour, j'ai un DM à rendre pour demain en mathématiques. C'est sur les identité remarquables. Merci de m'aider.
Voici la première expression:
C=
La deuxième expression:
D=
Merci d'avance de me répondre.
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draneur29
Verified answer
Alors c=2*(3t^2-3t*5*2+5^2)-2(1^2-2*1*4t+4t^2)
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maudmarine
C = 2 (3t - 5)² - 2 (1 - 4t)²
C = 2 (9t² - 30t + 25) - 2 (1 - 8t + 16t²)
C = 18t² - 60t + 50 - 2 + 16t - 32t²
C = 18t² - 32t² - 60t + 16t + 50 - 2
C = - 14t² - 44t + 48
D = (1 + 4y)² - (2y + 3)² - (1 + 4y) (2y + 3)
D = 1 + 8y + 16y² - (4y² + 12y + 9) - (2y + 3 + 8y² + 12)
D = 1 + 8y + 16y² - 4y² - 12y - 9 - 2y - 3 - 8y² - 12
D = 16y² - 4y² - 8y² + 8y - 12y - 2y + 1 - 9 - 3 - 12
D = 4y² - 6y - 23
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math0fanny
Merci beaucoup, c'est vraiment mon point faible je te remercie ! :)
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Verified answer
Alors c=2*(3t^2-3t*5*2+5^2)-2(1^2-2*1*4t+4t^2)C = 2 (9t² - 30t + 25) - 2 (1 - 8t + 16t²)
C = 18t² - 60t + 50 - 2 + 16t - 32t²
C = 18t² - 32t² - 60t + 16t + 50 - 2
C = - 14t² - 44t + 48
D = (1 + 4y)² - (2y + 3)² - (1 + 4y) (2y + 3)
D = 1 + 8y + 16y² - (4y² + 12y + 9) - (2y + 3 + 8y² + 12)
D = 1 + 8y + 16y² - 4y² - 12y - 9 - 2y - 3 - 8y² - 12
D = 16y² - 4y² - 8y² + 8y - 12y - 2y + 1 - 9 - 3 - 12
D = 4y² - 6y - 23