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Bibi38
@Bibi38
April 2019
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Bonjour j'ai un exercice en mathématique mais je comprend pas merci de M'aidé:
On considère l'expression
C=(5x-3)(3x+4)-(3x+4)²+2x(3x+4)
a) Développer et réduire l'expression C.
b) Montrer que C = (3x+4)(4x-7) .
C) Calculer C pour x =2 PUIS pour x = 5
Merci beaucoup pour votre aide !
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Commentaires (10)
Bonjour ,
a)
C =
(5x-3)(3x+4)-(3x+4)²+2x(3x+4)
C = 15x² + 20x - 9x - 12 - [ (3x)² + 4² - 24x ] + 6x² + 8x
C = 15x² + 11x - 12 - 9x² - 16 + 24x + 6x² + 8x
C = 12x² + 43x - 28
b) On factorise :
C =
(5x-3)(3x+4)-(3x+4)²+2x(3x+4)
C = (3x+4) [ (5x-3) - (3x+4) + 2x ]
C = (3x+4) (5x-3-3x-4+2x ]
C = (3x+4) (4x-7)
c) *pour x = 2
(3x+4) (4x-7)
(3(2)+4) (4(2)-7)
(6+4) (8-7)
10
× 1
C = 10
* pour x = 5
(3(5)+4) (4(5)-7)
(15+4) (20-7)
19 × 13
C = 247
1 votes
Thanks 2
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a)
C = (5x-3)(3x+4)-(3x+4)²+2x(3x+4)
C = 15x² + 20x - 9x - 12 - [ (3x)² + 4² - 24x ] + 6x² + 8x
C = 15x² + 11x - 12 - 9x² - 16 + 24x + 6x² + 8x
C = 12x² + 43x - 28
b) On factorise :
C = (5x-3)(3x+4)-(3x+4)²+2x(3x+4)
C = (3x+4) [ (5x-3) - (3x+4) + 2x ]
C = (3x+4) (5x-3-3x-4+2x ]
C = (3x+4) (4x-7)
c) *pour x = 2
(3x+4) (4x-7)
(3(2)+4) (4(2)-7)
(6+4) (8-7)
10 × 1
C = 10
* pour x = 5
(3(5)+4) (4(5)-7)
(15+4) (20-7)
19 × 13
C = 247