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Mal850
@Mal850
May 2019
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Bonjour , j'ai un exercice sur les vecteurs , Pourriez-vous m'aider a faire la première questions Svp ?Merci d'avance
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christelle75
3NA-2NB=0
3NA-2NA-2AB=0 (par relation de chasles dans NB)
NA-2AB=0
NA=2AB
AB(xb-xa ; yb-ya)
AB(4-1 ; 3-2)
AB(3 ; 1)
NA(xa-xn ; ya-yn)
xa-xn=2×3 (NA=2AB donc 2xAB=xNA)
1-xn=6
-xn=5
xn=-5
ya-yn=2×1 (NA=2AB donc 2xAB=xNA)
2-yn=2
-yn=0
yn=0
N(-5 ; 0)
1 votes
Thanks 1
christelle75
pas de quoi
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3NA-2NA-2AB=0 (par relation de chasles dans NB)
NA-2AB=0
NA=2AB
AB(xb-xa ; yb-ya)
AB(4-1 ; 3-2)
AB(3 ; 1)
NA(xa-xn ; ya-yn)
xa-xn=2×3 (NA=2AB donc 2xAB=xNA)
1-xn=6
-xn=5
xn=-5
ya-yn=2×1 (NA=2AB donc 2xAB=xNA)
2-yn=2
-yn=0
yn=0
N(-5 ; 0)