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MinatoNM
@MinatoNM
May 2019
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Bonjour J'ai un problème avec un devoir de physique sur le tube de Venturi merci pour vos réponses
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scoladan
Verified answer
Bonjour,
Bernouilli : DeltaP = 1/2p(v1^2 - v2^2)
v1 = Q/S1 et v2 = Q/S2
==> DeltaP = 1/2pQ^2 /(S1^2 - S2^2)
==> Q^2 = 2xDeltaPx(S1^2 - S2^2)/p
p = 1000 kg.m^-3
DeltaP = 1,200.10^4 Pa
S1 = 2 x S2
Q^2 = 2x1,2.10^4x 3 x (50,25^2 x 10^-4) x10^-3
= 18,18045
==> Q = Racine(18,18045) = 4,26 m^3.s^-1
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Lista de comentários
Verified answer
Bonjour,Bernouilli : DeltaP = 1/2p(v1^2 - v2^2)
v1 = Q/S1 et v2 = Q/S2
==> DeltaP = 1/2pQ^2 /(S1^2 - S2^2)
==> Q^2 = 2xDeltaPx(S1^2 - S2^2)/p
p = 1000 kg.m^-3
DeltaP = 1,200.10^4 Pa
S1 = 2 x S2
Q^2 = 2x1,2.10^4x 3 x (50,25^2 x 10^-4) x10^-3
= 18,18045
==> Q = Racine(18,18045) = 4,26 m^3.s^-1