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Lina69000
@Lina69000
January 2021
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Bonjour, j'ai vraiment besoin d'aide pour ce devoir.
Pouvez-vois m'aider?
Merci pour vos reponses.
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calinizou
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Bonjour
volume pyramide h*aire de base le tout diviser par 3 donc 15*(8*11)/3=440cm cube
sb=17
pythagore
sa²+ab²=sb²
15²+8²=sb²
225+64=289=sb²
donc sb =racine carré de 289 =17
après j appliquerais thalès
sf/sb=se/sa=ef/ab 13.6/17=12/15=6.4/8 pour ef tu fais 8*12:15=6.4
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Lina69000
Merci beaucoup pour votre réponse! Il s'agit des reponses de quelle questions?
calinizou
réponse 1 2 et 3
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Bonjourvolume pyramide h*aire de base le tout diviser par 3 donc 15*(8*11)/3=440cm cube
sb=17
pythagore
sa²+ab²=sb²
15²+8²=sb²
225+64=289=sb²
donc sb =racine carré de 289 =17
après j appliquerais thalès
sf/sb=se/sa=ef/ab 13.6/17=12/15=6.4/8 pour ef tu fais 8*12:15=6.4