Articles
Register
Sign In
Search
enihs
@enihs
January 2021
1
92
Report
Bonjour j'aimerais de l'aide pour cette question : Factorisez 3n^2+7n+4 puis en deduire le PGCD de ((n+1)^2;3n^2+7n+4)
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
aymanemaysae
Bonsoir ;
On a : 3n² + 7n + 4 = 3n² + 3n + 4n + 4 = 3n(n + 1) + 4(n + 1)
= (n + 1)(3n + 4) .
On a aussi : PGCD((n + 1)² ; 3n² + 7n + 4) = PGCD((n + 1)² ; (n + 1)(3n + 4))
= (n + 1) PGCD(n + 1 ; 3n + 4) = (n + 1) PGCD(n + 1 ; 3(n + 1) + 1)
= n + 1 car PGCD(n + 1 ; 3(n + 1) + 1) = 1 .
0 votes
Thanks 1
enihs
D'accord merci... Il fallait vraiment le trouver...
aymanemaysae
De rien .
More Questions From This User
See All
enihs
February 2021 | 0 Respostas
Responda
enihs
February 2021 | 0 Respostas
Responda
enihs
February 2021 | 0 Respostas
Responda
enihs
February 2021 | 0 Respostas
Responda
enihs
February 2021 | 0 Respostas
Responda
enihs
February 2021 | 0 Respostas
Bonjour comment pmacer les points C et D dans un repere s'il vous plait ? Merci d'avance
Responda
enihs
January 2021 | 0 Respostas
Responda
enihs
January 2021 | 0 Respostas
Bonjour, j'aimerais de l'aide pour la question 3.a et 3.b svp
Responda
enihs
January 2021 | 0 Respostas
Bonjour j'aimerais une explication sur comment remonter l'algo d'euclide svp ?
Responda
Enihs
May 2019 | 0 Respostas
Responda
×
Report "Bonjour j'aimerais de l'aide pour cette question : Factorisez 3n^2+7n+4 puis en deduire le PGCD de (.... Pergunta de ideia de enihs"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
On a : 3n² + 7n + 4 = 3n² + 3n + 4n + 4 = 3n(n + 1) + 4(n + 1)
= (n + 1)(3n + 4) .
On a aussi : PGCD((n + 1)² ; 3n² + 7n + 4) = PGCD((n + 1)² ; (n + 1)(3n + 4))
= (n + 1) PGCD(n + 1 ; 3n + 4) = (n + 1) PGCD(n + 1 ; 3(n + 1) + 1)
= n + 1 car PGCD(n + 1 ; 3(n + 1) + 1) = 1 .