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a)BC=393-251
BC=142m
b)Dans le triangle CBA rectangle en B on a:
sin (CAB)=BC/AC
sin 12°=142/AC
AC=142/sin(12)
AC≈683m
c)tan(CAB)=BC/AB
tan 12°=142/AB
AB=142/(tan12)≈668m
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a)BC=393-251
BC=142m
b)Dans le triangle CBA rectangle en B on a:
sin (CAB)=BC/AC
sin 12°=142/AC
AC=142/sin(12)
AC≈683m
c)tan(CAB)=BC/AB
tan 12°=142/AB
AB=142/(tan12)≈668m